$2x+8=5x-4$
$=\left(2x-y+5\right)^2\left(x^2+x+1\right)^2$
$\left(2.99\right)^{12}$
$13r+5s-2r$
$\left(3+xy\right)\left(7-xy\right)$
$4cos^2x-1=0$
$\lim_{x\to\infty}\left(1-\frac{2}{x}\right)^{4x}$
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