$3+\frac{x}{2}\ge5x$
$\frac{dy}{dx}y+4x=0$
$f\left(x\right)=tanx^2sec\:x$
$6r^2-6-5r$
$\left(-\:5xy^4+\:3x^2\:y^2\:\right)\left(-\:5xy^4-\:3x^2\:y^2\:\right)$
$11-\:\left(-4\right)$
$\left(x+\frac{1}{2}\right)^2+\left(y-1\right)^2\le\frac{5}{4}$
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