$21\cdot e^{3\cdot\infty}$
$\left(7x\:+\:1\right)^3$
$y\left(x^2+4\right)$
$2\left(6\right)\left(-2\right)$
$e^7=y$
$\frac{x}{x+3}+1\ge0$
$8-\left[10+2\left(x+5\right)\right]$
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