$\int\frac{\left(x^4+8x^2+8\right)}{\left(x^3-4x\right)}dx$

$\frac{-3y+3y^4+y+\frac{1}{6}y^4+\frac{3}{2}}{4y-1-2y}$

$15+0.54$

$\int_0^2\left(6-x\right)dx$

$\int_3^{\infty}\left(\frac{1}{4x}\right)dx$

$\left(x+3y-1\right)\left(2x+4y-3\right)$

$9\:cos^2\:\left(x\right)+81$