$\frac{\left(1+y^{\frac{1}{2}}\right)dy}{y+1}=\frac{1}{x^{\frac{1}{2}}}dx$

$\left(x^2-1\right)\frac{dy}{dx}+2xy=0$

$\left(2+2\right)\cdot\left(-4\right)$

$\left(\frac{4x-1}{x+3}\right)-2\ge\left(\frac{9}{x+3}\right)$

$\left(4b-7v\right)^2$

$\int\frac{\left(\sqrt{x}-1\right)^3}{\sqrt{x}}.dx$

$7\left(x+4\right)-5\left(x+6\right)+6$