$-16\left(13q+7\right)+8q$
$\frac{x-1}{x^2-4x+4}$
$3r\:+\:2b-\:9r$
$\left(5x+6\right)\left(x+3\right)$
$\frac{dq}{dt}=-4q+12$
$\frac{dy}{dx}\left(\tan\left(y\right)=e^2+\ln\left(7x\right)\right)$
$-4+5-6+7-3+6-9+4-5$
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