$7,453\cdot2,632$
$3x^2y-6xy^2+12xy$
$h\left(z\right)=\left(6-z^2\right)\left(z^3-5z+3\right)$
$\frac{2x-5}{12}=\frac{x}{4}-\frac{5}{3}$
$\frac{a^{18}-c^9}{9^2+c}$
$-2.2+5u=10.3$
$\frac{dy}{dx}=4x=10y$
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