$0\cdot\left(-9\right)$
$\left(5y\:-\:3z\right)\:\left(4x\:-\:7z\right)$
$\lim_{x\to4}\left(x^2-5\right)$
$\frac{sin\left(2\left(x-3\right)\right)}{sin\left(x-3\right)}$
$\:\:5^2\:\cdot\:2^3$
$q\left(x\right)=\sqrt{2mx^{3m-3}+3mx^{2m+2}}$
$11x^5+7x^3-13x^5+6x^4$
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