$\lim_{x\to0}\:\frac{\left(\left(2+x\right)^2-5\left(2+x\right)-6\right)}{x}$
$\left(x^6y^7\right)^{-2}$
$x^2+7x-144=0$
$x^2+24x+140=0$
$y'=\left(cos^2xsen2x\right)$
$\lim_{x\to4}\frac{x^2-6x+22}{x+3}$
$\int\left(\left(ln\left(7x\right)\right)^22x\right)dx$
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