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$\int\left(\frac{3x}{\left(x^2+2\right)^4}\right)dx$

Final answer to the exercise

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Other solved exercises

$\left(3x-1\right)\left(2x-8\right)$

$8^3-1$

$f\left(x\right)=\frac{x}{\left(x^2-2x+1\right)}$

$3y'+4y=2$

$3x=9x$

$ln\:x^{\frac{1}{2}}$

$-x^4+16$
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