$\frac{dy}{dx}\left(4x^2-9y^2=36\right)$
$\left(x^3-\sqrt{8}\right)\left(x^3+\sqrt{8}\right)$
$\left(-26+39\right)\cdot\left(14-3\cdot6\right)$
$\sqrt[5]{k^6m^4}\cdot\sqrt[5]{k^8m^3}$
$x2-9x+18$
$7x\:and\:-9x$
$\frac{dy}{dx}+y\cos\left(x\right)=4\cos\left(x\right)$
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