$16x^6+8x^3y^2+y^4$
$-499-275-334$
$\sqrt{144z^2}$
$\lim_{x\to0}\left(\frac{e^{x}-1}{x^{3}}\right)$
$\lim_{x\to\infty}\left(1+\frac{1}{x+2}\right)^{4x}$
$\frac{9yx^2}{3xy}$
$2y-y+7-1+3+7x^2-4y$
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