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$\int\left(\frac{2x^2+3}{\left(x^2+1\right)}\right)dx$

Final answer to the exercise

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Other solved exercises

$29\cdot\lim_{x\to-2}\left(\frac{x^2-4}{x}\right)$

$\left(\:4x\:+\:2\right)\:\left(\:7x\:-9\right)\:$

$3.625+2\cdot t=4.175$

$5x-3x^2+1$

$5\sin^2\left(x\right)=3\sin\left(x\right)$

$-3.8\cdot4.44$

$45\cdot9$
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