$\left(5xy^2\right)^4$
$\left(5q^2\:-\:6\right)\left(5q^2\:+\:6\right)$
$\frac{-2a+4}{4}\cdot12$
$-6-7-3-5$
$\left(-2\right)^2\cdot\left(-9\right)$
$-x^3-3x^2-17x-8$
$3\cos\left(x\right)-6\sin\left(x\right)\cos\left(x\right)=0$
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