$\int\frac{x}{5x^2+3x}dx$
$-4x\:x\:y\:x\:0^6$
$\:\:x+4x-5x$
$\frac{dy}{dx}-4xy=\frac{5x}{4}$
$\left(2x^2\right)\left(2y^3\right)$
$\frac{28x^2-30y^211xy}{4x-5y}$
$\int\frac{10}{x^2-6x-7}dx$
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