$18x^2-3x-6$
$\left(3x^2\right)\left(8x^3-7\right)$
$\left(\sqrt[5]{a}\right)^5$
$\sqrt[5]{x^2\sqrt[4]{x-3}}$
$-39\:\cdot\:7$
$2x\:\le\:2\:\left(x-1\right)$
$\int4x^2-8xdx$
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