$-3x^2+7x+5$
$\frac{x^2+12x+12}{x\left(x^2-4\right)}$
$\lim_{x\to0}\frac{\left(e^x-\left(1-11x\right)\right)}{x}$
$\ln\left(x\right)+4\ln\left(y\right)$
$7-6n-3n$
$r^2-14r+8=0$
$\lim_{x\to\infty}\left(\frac{\ln\left(3x+10\right)}{\ln\left(10x+8\right)+1}\right)$
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