$3x+2x^4$
$\frac{d}{dx}\frac{y+4}{x+3}$
$\frac{x-5}{x-3}\le\:16\:$
$\left(v^{-2}\right)^3=v^6\cdot v^x$
$4tan\:x\:-3\:=\:-5$
$\int\cos\left(wx\right)dx$
$-x^2-10x-8=0$
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