$17+\left(-3\right)\cdot5+4$
$\csc2x=\cot x-\cot2x$
$\int\sqrt[3]{1-3x\:}dx$
$\left(x-1\right)^2+5\ge\left(x-3\right)^2$
$x2-5x+2x$
$\int\left(5e^{5x}\left(1+2e^{5x}\right)^4\right)dx$
$x^2+4x=1$
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