$\left(5x^2+2x\right)^3$
$\ln\left(x+2\right)+\ln\left(3x-12\right)=\ln\left(2x-2\right)+\ln x$
$y^2-6y+10=0$
$\frac{d}{dx}8\sqrt[3]{x^5}-\frac{2}{5x^2}+\frac{2}{3}$
$435,28+4$
$m^2+2mn+n^2;\:m=4;\:n=-2$
$8\cdot.9503$
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