$\lim_{x\to3}\left(\frac{\tan\left(-4-2x\right)-3x^2}{3x+6}\right)$
$\left(7e+9\right)\left(7e-9\right)^2$
$-145\:+\:830$
$x^6+4^4$
$\left(\frac{14}{3}\right)-\left(\frac{2}{3}\right)$
$\frac{3x}{4}-2\ge10$
$5x^2-6x+3-\left(7x^2-2x+8\right)$
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