$\frac{dy}{dx}=\left(\frac{x}{y}\right)+\left(\frac{y}{x}\right)+1$
$k^2-24k-25=0$
$\lim_{x\to\infty}\left(\frac{5x+1}{e^x+1}\right)$
$\left(-6\right)\cdot\left(-4\right)$
$\frac{\left(-3-5\right)}{2}$
$4e^5-2e^3$
$4xy^2=x^2$
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