$\frac{\tan\left(x\right)^2}{\sec\left(x\right)+1}=\tan\left(x\right)$
$3\:\sin u\:-\:\cos^2\:u\:-\:3\:=0$
$4\sqrt{2}x\sqrt{48}$
$-12=2+5v+2v$
$9.6+5.8$
$-12+3+45+99-2$
$-\frac{6}{3}$
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