$\frac{\left(\sqrt{3}-\sqrt{5}\right)\left(\sqrt{3}+\sqrt{5}\right)}{2}$
$\frac{du}{dt}=e^{5u+7t},\:u\left(0\right)=4$
$\left(2x-3y+xy\right)^2$
$\frac{16y^7-24y^5+40x^4}{8y^2}$
$x^4-3x^2+4$
$\sqrt[30]{2}^{40}.3^{34}$
$\frac{x^4-2x^2+4}{x-2}$
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