$\frac{2x^3+6x^2+6}{-3}$
$\cos\left(2x\right)+3\cos\left(x\right)=-1$
$\left(8j+5\right)-\left(5j+5\right)$
$x-9<15$
$\cos x=\frac{3}{4}$
$-9-25+17+-35$
$\lim_{x\to\infty}\left(e^{-x}\right)dx$
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