$\int\frac{x^4-1\:\:\:\:\:}{x^2+1}\:dx$
$9x^2-18x+16$
$\frac{\left(50\right)}{\left(-10\right)}$
$3000+1400$
$7x\cdot3a$
$\left(+\sqrt{2}\right)\left(-\sqrt{2}\right)$
$1x^2-100$
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