$\lim_{x\to\infty}\left(\ln\left(\frac{2x+1}{x+3}\right)\right)$
$n^2+32n+\left(\frac{32}{2}\right)^2$
$\frac{1}{1-sin^2\left(y\right)}=1+tan^2y$
$\left(x-4y\right)^5$
$( 4 ) ^ { 2 } - ( 6 ^ { 5 } )$
$2x^2+5x+6$
$-3+4+2+1$
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