$546-398$
$\int_0^{\frac{\pi}{15}}x\:tan^2\left(5x\right)dx$
$x^2+10+1$
$\tan\left(x\right)=\frac{\sin\left(5x\right)-\sin\left(3x\right)}{\cos\left(5x\right)+\cos\left(3x\right)}$
$\left(x+\frac{3}{2}\right)\left(-x+\frac{3}{2}\right)$
$5x+3\le3x+1$
$4\left(sinx\right)^2=2$
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