$\lim_{x\to0}\left(x-5\right)$
$\left(3ab^{x}\right)\left(a^{2}c^{5}\right)$
$\int\frac{x^3}{\left(x+3\right)\left(x^2-4x+5\right)}dx$
$3.6-9$
$x^2+x\:=\:42$
$\frac{6}{4.8}$
$-\frac{1}{2}x>=\frac{23}{4}$
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