$a^2=12$
$\sqrt{-11}$
$f\left(x\right)=\frac{1}{\tan\left(x-5\right)}$
$3x+12=8x-38$
$\int\left(3x+6\right)^{10}dx$
$m^2-20=_{-8m}$
$xy=36$
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