$\lim_{x\to\infty}\frac{3x-3}{x^2-4x+3}$
$-2^2+17-15x+7xy$
$\frac{d^5}{dx^5}\:x^5$
$20-3x=x+4$
$\left(2x^2y^4+6a^5b^3\right)\left(2x^2y^4-6a^5b^3\right)$
$\int\left(-x^2\:+\:6x-8\right)^2dx$
$\frac{7x^2-3x+1}{x-1}$
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