$\int\frac{x^3+4}{x\left(x-2\right)^3}dx$
$10x^4-6x^2$
$\int\frac{x+5}{\left(2x-5\right)\left(x-2\right)}dx$
$\int\frac{5x^2-36x+48}{\left(x-4\right)^2}dx$
$\frac{dy}{dx}-y=2x+1$
$15^1\cdot15^0$
$2x^2\:+\:2x\:+\:xy\:=\:5\:$
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