$9x^2+18x$
$\int10\cos\left(10x\right)dx$
$\frac{dy}{dx}=\frac{xy^3}{\sqrt{1-x^2}}$
$4\left(7+5\right)$
$\frac{dy}{dx}=\frac{-5x}{6y}$
$\left(6a^4-6b^2\right)^2$
$\left(6a^2-b^4\right)\left(6a^2+b^4\right)$
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