$\frac{4x^3-9x^2+5x-11}{x-2}$
$\frac{dy}{dx}=\tan\left(3x+4\right)$
$v^2+12v$
$\ln\left(x+31\right)-\ln\left(3-2x\right)=5\ln\left(2\right)$
$\left(6y^4-5\right)^2$
$x2-8x=8$
$\frac { ( 0.02435 ) ( 53.125 ) } { ( 142.356 ) ( 0.189 ) }$
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