$\left(x+3y\right)\left(4a+12x\right)$
$10x-x+4y-9x$
$-35-\left\{-45-\left[-\left(5-28\right)-\left(-17\right)\right]\right\}$
$\frac{80}{16}$
$x\left(\frac{-1}{\sqrt{1-x^2}}\right)$
$3-5x=-9+x$
$\left(6x+12y\right)\left(6x+12y\right)$
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