$\frac{d}{dx}\sqrt[3]{1+x^5}$
$\lim_{x\to4}\left(1\right)$
$\sqrt[3]{0.008}$
$\frac{\sec^6\frac{3y^2x}{x^2y}}{5}=0$
$2\left(-3\right)+9$
$\int\left(\frac{1}{256x^2-49}\right)dx$
$\left(x^3+\frac{1}{3}\right)\left(x^3-\frac{3}{4}\right)$
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