$\int\frac{\left(xye^{xy}\right)}{\left(1+xy\right)^2}dx$

$\frac{\tan^{2}b}{\secb}=\senb\cdot\tanb$

$y=\left(5+8x^{-3}\right)\left(-5x^2+2-4x\right)$

$\left(+8\right)x\left(+3\right)$

$\left(a+0.8\right)^2$

$x^2-4x+42$

$\left(\sqrt{s}+\sqrt{s}x\right)dx=\left(x+1\right)ds$