$\left(4n^4.n\right)^2$
$\int\left(x\cdot\sqrt{x^8-3}\right)dx$
$12a^2-11a+6$
$\int\frac{6x^2+x+6}{\left(x^2+2\right)\left(x-6\right)}dx$
$-4x+15\:=\:19$
$4x^3-9x+8-5x^3+3$
$2ab+4a-9b-18$
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