$\int_1^{\infty}\left(\frac{e-\sqrt{x}}{\sqrt{x}}\right)dx$
$\int3\left(1+tan^2x\right)dx$
$7\tan\left(x\right)=1$
$\left(-7r-3b\right)\left(-7r+3b\right)$
$\int\frac{\ln\left(8x-23\right)}{\ln\left(8\right)}dx$
$-7x+3\ge-18$
$16x^2-24x=2$
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