$x^2-4x=12$
$2x^2+y^2=1$
$\left[\left(-\:25\right)\::\:5\:+\:\left(8\:-\:4\::\:2\right)\right]\:$
$\left(\:x\:-\:5\:\right)\:.\:\left(\:x\:+\:3\:\right)$
$x^2-8x+9.75$
$5x^3+2x^2-4x+6-2x^3-3x^2-6x+9$
$\int_0^{1-x}\left(1\right)dx$
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