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Rewrite the fraction $\frac{x}{\left(\sqrt{x}\right)^2+1}$ inside the integral as the product of two functions: $x\frac{1}{\left(\sqrt{x}\right)^2+1}$
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$\int x\frac{1}{\left(\sqrt{x}\right)^2+1}dx$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int(x/(x^1/2^2+1))dx. Rewrite the fraction \frac{x}{\left(\sqrt{x}\right)^2+1} inside the integral as the product of two functions: x\frac{1}{\left(\sqrt{x}\right)^2+1}. We can solve the integral \int x\frac{1}{\left(\sqrt{x}\right)^2+1}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.