$\lim_{x\to2}\left(\frac{x^2-4x+4}{x^2-2x}\right)$
$9x^2+6x$
$4\le x^2-12x+9$
$\left(3x-7y^4\right)^2$
$-12x\:+\:13=-59$
$y^2dy-\frac{1+x}{x^2}dx=0$
$\frac{x+2}{3}+\frac{x-3}{2}\ge5$
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