$16-2v+3$
$\left(2+4y^2\right)^3$
$\frac{3.14}{90}$
$f^2+7f+11$
$\left(-4\left(x-3\right)-8<=5-x\right)$
$\frac{d^2}{dx^2}\left(\sqrt{y}+xy=1\right)$
$dy=\frac{\left(y\:+\:\sqrt[2]{y}\right)}{\left(\sqrt[2]{x}\:+\:x\:\right)}\:dx$
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