$\frac{11.96}{4}$
$20-\left(-7\right)$
$\frac{\left(-62+20-8-12\right)}{31}$
$\frac{3x^2-4x-120}{x+4}$
$\int\left(2x-1\right)\left(x^2-x+5\right)^6dx$
$\left(5m^4n+7p^5\right)^3$
$\frac{d}{dx}arctanx^3$
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