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Exercise

$\int\frac{x^4-x^3+2x^2-8}{x^2-4}dx$

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Final answer to the exercise

$\frac{x^{3}}{3}-\frac{1}{2}x^2+6x-4\ln\left|x+2\right|+4\ln\left|x-2\right|-4\ln\left|\sqrt{x^2-4}\right|+C_1$

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  • Integrate by partial fractions
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