$\left(x+3\right)\left(x-5\right)+\left(x-1\right)^2$
$\lim_{x\to-1}\left(\frac{5x^4+4x^3+6x+5}{x+1}\right)$
$4xy^2\cdot3x^{-4}y^5$
$\frac{2}{x-1}<-3$
$-16+y=-13$
$4x^2+8x$
$f\left(x\right)=-\frac{3\sqrt{x^3}}{2}-\frac{1}{x}$
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