$2+6\infty$
$-9-4+2$
$\frac{\frac{1}{3}x^3+6x^2-3x+8}{\frac{x}{3}}$
$\frac{dy}{dx}=x^2-.5y$
$3k^2+12k-9=0$
$\frac{d}{dx}\sqrt[2]{x+y}=8+x^2y^2$
$\int\frac{8x-64}{x^2\left(x^2+64\right)}dx$
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