$-x-10<5x+4$
$5y+1=6$
$x^2+x-x-x$
$\lim_{x\to2.99}\:\left(\frac{x-3}{x^2-9}\right)$
$\left(3x^3+y^5\right)^2$
$24x\:\left(\frac{1}{2}\right)^2\:x\:\left(\frac{1}{3}\right)^3\:x\:\left(\frac{1}{4}\right)$
$-19=x-19$
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