$\left(2\:x-3\right)+3$
$2\left(3^3\right)-7$
$\:-12\:.\:3\:+\:18\::\:\left(\:-12\::\:6\:+\:8\:\right)$
$9 x ^ { 4 } - 12 x y + 27 x ^ { 2 }$
$\frac{4x-10}{2}$
$\lim_{x\to-0.99}\frac{\tan\left(-0.99\right)}{\sin\left(-0.99\right)}$
$x^2-4x+-4$
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