$\int\sqrt{16+6x-x^2}dx$

$\lim_{x\to-3}\left(2x^4-5x^3+7x\right)$

$1.66\:+\:4.5\:-\:0.67\:$

$\left(\frac{3}{2}x^2+4y^5\right)\cdot\:\left(\frac{3}{2}x^2-8y^7\right)$

$\left(6-7x^2y\right)\left(6+7x^2y\right)$

$\frac{\left(1-cos\left(x\right)\right)^2}{sin\left(x\right)^2}$

$\int_{-2}^{4}xdx$